Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The common tangent of the parabolas y 2 = 4x and x 2 = –8y is -
Text Solution
Verified by ExpertsThe correct answer is:
D
y 2 = 4x ...(1)
⇒ 4a = 4 ⇒ a = 1
equation of tangent of parabola (1) is
y = mx + a/m ⇒ y = mx + 1/m ...(2)
Another parabola is x 2 = – 8y ...(3)
Now, line (2) touches the parabola (3) then the equation x 2 = –8 
has equal roots
⇒ Discriminant = 0 ⇒ m = ?
put in 2
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